SOLUTION: a2b + 3a2 + 2b + 6

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Question 323840: a2b + 3a2 + 2b + 6
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
This appears to be a FACTORING problem!

a%5E2b%2B3a%5E2%2B2b%2B6

This is a GROUPING problem in which you group the first two and the last two terms:
a%5E2%28b%2B3%29+%2B+2%28b%2B3%29

Now, take out the common factor of (b+3):
%28b%2B3%29%28a%5E2+%2B+2%29+

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Seminole State College of Florida
Altamonte Springs Campus