Question 323827: The perimeter of a rectangle is 106 inches. The length exceeds the width by 19 inches. Find the length and the width.
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x = width
x+19 = length
The equation is 2W + 2L = P
2(x) + 2(x+19) = 106
2x+2x+38=106
4x+38=106
4x=106-38
4x=68
x=68/4=17 inches WIDTH
x+19=17+19=36 inches LENGTH
Check: 2*17+2*36
34+72=106
It checks!!!
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