SOLUTION: 1.) y = 6x^2 - 5x y = 2x + 3 2.) y = x^2 - 3x -3 y = -x^2 + 5x + 7

Algebra ->  Systems-of-equations -> SOLUTION: 1.) y = 6x^2 - 5x y = 2x + 3 2.) y = x^2 - 3x -3 y = -x^2 + 5x + 7       Log On


   

Question 323821: 1.) y = 6x^2 - 5x
y = 2x + 3
2.) y = x^2 - 3x -3
y = -x^2 + 5x + 7
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
#1:
1.+y+=+6x%5E2+-+5x
2.++++y+=+2x+%2B+3
Since they both equal y, set them equal to each other.
6x%5E2-5x=2x%2B3
6x%5E2-7x-3=0
%282x-3%29%283x%2B1%29=0
Two solutions:
2x-3=0
2x=3
x=3%2F2
The use either equation to solve for y,
y=2%283%2F2%29%2B3=6
(3/2,6)
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3x%2B1=0
3x=-1
x=-1%2F3
y=2%28-1%2F3%29%2B3=9%2F3-2%2F3=7%2F3
(-1/3,7/3)
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#2: Same approach
1.+y+=+x%5E2+-+3x+-3
2.y+=+-x%5E2+%2B+5x+%2B+7
x%5E2-3x-3=-x%5E2%2B5x%2B7
2x%5E2-8x-10=0
x%5E2-4x-5=0
%28x-5%29%28x%2B1%29=0
Two solutions:
x-5=0
x=5
y=%285%29%5E2-3%285%29-3=7
(5,7)
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x%2B1=0
x=-1
y=%281%29%5E2-3%28-1%29-3=1
(-1,1)
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