SOLUTION: The length of a rectangle is 1 yd more than twice its width, and the area of the rectangle is66 yd . Find the dimensions of the rectangle...
Algebra ->
Rectangles
-> SOLUTION: The length of a rectangle is 1 yd more than twice its width, and the area of the rectangle is66 yd . Find the dimensions of the rectangle...
Log On
Question 323736: The length of a rectangle is 1 yd more than twice its width, and the area of the rectangle is66 yd . Find the dimensions of the rectangle... Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! L=2W+1
A=LW
66=(2W+1)W
66=2W^2+W
2W^2+W-66=0
(2W-11)(W+6)=0
2W-11=0
2W=11
W=11/2
W=5.5 ans.
L=2*5.5+1=11+1=12 ans.
Proof:
66=12*5.5
66=66
(