SOLUTION: There is a flood. A large culvert washes out. To repair the road workers replace the old 6' by 25' culvert (cylinder) with two 4'x 25' culverts. Which can carry the greatest vol

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Question 323703: There is a flood. A large culvert washes out. To repair the road workers replace the old 6' by 25' culvert (cylinder) with two 4'x 25' culverts. Which can carry the greatest volume of water; the two new smaller culverts or the old larger one?
Found 2 solutions by Fombitz, Alan3354:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The volume of a cylinder is,
V=pi%2AR%5E2%2AH
The old culvert could hold,
V1=pi%2A%286%29%5E2%2A25=36%2A%2825pi%29
The two new culverts can hold,
V2=2%2Api%2A%284%29%5E2%2A25=32%2A%2825pi%29
As you can see the old culvert holds more than the new ones (32 vs. 36).

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
There is a flood. A large culvert washes out. To repair the road workers replace the old 6' by 25' culvert (cylinder) with two 4'x 25' culverts. Which can carry the greatest volume of water; the two new smaller culverts or the old larger one?
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The 6' has a greater cross-sectional area than 2 4' culverts.
It's a function of the square of the diameter.
6%5E2+=+36
2%2A4%5E2+=+32