SOLUTION: write an equation in slope intercept form of the line satisfying the given condition. The line passes through (-5, 6) and is perpindicular to the line that has an x intercept of 3

Algebra ->  Linear-equations -> SOLUTION: write an equation in slope intercept form of the line satisfying the given condition. The line passes through (-5, 6) and is perpindicular to the line that has an x intercept of 3       Log On


   

Question 323701: write an equation in slope intercept form of the line satisfying the given condition. The line passes through (-5, 6) and is perpindicular to the line that has an x intercept of 3 and a y intercept of -9
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First find the line it's perpendicular to,
x%2F3-y%2F9=1
y%2F9=x%2F3-1
y=3x-9
This line has a slope of m=3
Perpendicular lines have slopes that are negative reciprocals,
m1%2Am2=-1
3%2Am2=-1
m2=-1%2F3
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Use the point-slope form of a line with point (-5,6) and slope (m=1/3)
y-yp=m%28x-xp%29
y-6=%28-1%2F3%29%28x-%28-5%29%29
y-6=-%281%2F3%29x-5%2F3
highlight%28y=-%281%2F3%29x%2B13%2F3%29
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