Question 323414: Probability: find the indicated probabilities. Using the following information. Show your work.
In a sample bag of M&M's candy there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.
What is the probability of getting 1 green M&M if only one is taken at a time?
What is the probability of getting 3 yellow M&M's if 3 are taken at a time?
What is the probability of getting 1 brown and 2 orange M&M's if 3 are taken at a time?
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! 5 Brown
6 Yellow
4 Blue
3 Green
2 Orange
20 Total
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P(1 Green)=3/20
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P(1st Yellow)=6/20
P(2nd Yellow)=5/19
P(3rd Yellow)=4/18
P(Y,Y,Y)=(6/20)(5/19)(4/18)=1/57
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P(1st Brown)=5/20
P(2nd Orange)=2/19
P(3rd Orange)=1/18
P(B,O,O)=(5/20)(2/19)(1/18)=1/684
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