SOLUTION: Unsure of how to type "X to the third" etc so it appears as X3 7-X..........X3+27 ___....x....________ X+3.........X2-9X+14 7X3+189-X4-27X.......6X3+147 ___________ __

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Unsure of how to type "X to the third" etc so it appears as X3 7-X..........X3+27 ___....x....________ X+3.........X2-9X+14 7X3+189-X4-27X.......6X3+147 ___________ __       Log On


   

Question 32327: Unsure of how to type "X to the third" etc so it appears as X3
7-X..........X3+27
___....x....________
X+3.........X2-9X+14

7X3+189-X4-27X.......6X3+147
______________ = ____________ Is This Correct? Thank You Very Much!
X3+4X2-13X+42......X4+4X2+14X

(That reads as 6X to the third plus 147 over
X to the 4th + 4X squared + 14X)
Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
[(7-x)/(x+3)][(x^3+27)/(x^2-9x+14)]
=[(7-x)/(x+3)][(x+3)(x^2-3x+9)/(x-7)(x-2)]
=[-(x-7)/(x+3)][(x+3)(x^2-3x+9)/(x-7)(x-2)]
= -(x^2-3x+9)/(x-2)
Answer: -(x^2-3x+9)/(x-2)