SOLUTION: (k-3)/(k-2)-(k-4)/(k-1)=(3k+2)/(k^2-3k+2)

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Question 323209: (k-3)/(k-2)-(k-4)/(k-1)=(3k+2)/(k^2-3k+2)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Use the common denominator k%5E2-3k%2B2=%28k-2%29%28k-1%29
%28k-3%29%2F%28k-2%29-%28k-4%29%2F%28k-1%29=%283k%2B2%29%2F%28k%5E2-3k%2B2%29


Multiply both sides by %28%28k-2%29%28k-1%29%29
k%5E2-4k%2B3-k%5E2%2B6k-8=3k%2B2
2k-5=3k%2B2
highlight%28k=-7%29