SOLUTION: please help...i tried to work the problem with the formula given
z=value-mean/standard deviation
According to a survey conducted by television advertisers, the average adult Ame
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-> SOLUTION: please help...i tried to work the problem with the formula given
z=value-mean/standard deviation
According to a survey conducted by television advertisers, the average adult Ame
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Question 322989: please help...i tried to work the problem with the formula given
z=value-mean/standard deviation
According to a survey conducted by television advertisers, the average adult American watches an average of 6.98 hours of television per day. The data is normally distributed with a standard devieation of 3.80 hours. Find the probability that a randomly selected person watches more than 8.00 hours of television a day.
8.00-6.98/3.80=6.163...is this correct? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! work the problem with the formula given
z=value-mean/standard deviation
According to a survey conducted by television advertisers, the average adult American watches an average of 6.98 hours of television per day. The data is normally distributed with a standard devieation of 3.80 hours. Find the probability that a randomly selected person watches more than 8.00 hours of television a day.
8.00-6.98/3.80=6.163...is this correct?
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Note: Your Formula is wrong; you always need parentheses in the numerator.
It should be z-value = (value-mean)/standard deviation
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z(8) = (8-6.93)/3.8 = 1.02/3.8 = 0.2684
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Cheers,
Stan H.
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