SOLUTION: The path of a basketball shot can be modeled by the equation h = -0.09d² + 0.9d + 2 where h is the height of the basketball, in metres, and d is the horizontal distance of the ball

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The path of a basketball shot can be modeled by the equation h = -0.09d² + 0.9d + 2 where h is the height of the basketball, in metres, and d is the horizontal distance of the ball      Log On


   

Question 322897: The path of a basketball shot can be modeled by the equation h = -0.09d² + 0.9d + 2 where h is the height of the basketball, in metres, and d is the horizontal distance of the ball from the player, in meters.
How far from the floor is the ball when the player releases it?
Answer by jessica43(140) About Me  (Show Source):
You can put this solution on YOUR website!
When the player first releases the basketball, the ball has not traveled any horizontal distance away from the player. This means that at the point of release, d=0 meters.
Now plug that into the equation to find the height:
h = -0.09d² + 0.9d + 2
h = -0.09(0)² + 0.9(0) + 2
h= 2 meters
The ball is 2 meters off the floor when the player first releases it.