SOLUTION: find distance between P and Q P( 4,9); Q(9, 21) P(6,-3); Q(-3, 2)

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Question 322840: find distance between P and Q
P( 4,9); Q(9, 21)
P(6,-3); Q(-3, 2)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first one to get you started.

# 1

Note: is the first point . So this means that x%5B1%5D=4 and y%5B1%5D=9.
Also, is the second point . So this means that x%5B2%5D=9 and y%5B2%5D=21.


d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29 Start with the distance formula.


d=sqrt%28%284-9%29%5E2%2B%289-21%29%5E2%29 Plug in x%5B1%5D=4, x%5B2%5D=9, y%5B1%5D=9, and y%5B2%5D=21.


d=sqrt%28%28-5%29%5E2%2B%289-21%29%5E2%29 Subtract 9 from 4 to get -5.


d=sqrt%28%28-5%29%5E2%2B%28-12%29%5E2%29 Subtract 21 from 9 to get -12.


d=sqrt%2825%2B%28-12%29%5E2%29 Square -5 to get 25.


d=sqrt%2825%2B144%29 Square -12 to get 144.


d=sqrt%28169%29 Add 25 to 144 to get 169.


d=13 Take the square root of 169 to get 13.


So our answer is d=13


So the distance between the two points P and Q is 13 units.