SOLUTION: Write a slope-intercept equation for a line that passes through (2,0) and (-2,5)

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Question 322837: Write a slope-intercept equation for a line that passes through (2,0) and (-2,5)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=2 and y%5B1%5D=0.
Also, is the second point . So this means that x%5B2%5D=-2 and y%5B2%5D=5.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%285-0%29%2F%28-2-2%29 Plug in y%5B2%5D=5, y%5B1%5D=0, x%5B2%5D=-2, and x%5B1%5D=2


m=%285%29%2F%28-2-2%29 Subtract 0 from 5 to get 5


m=%285%29%2F%28-4%29 Subtract 2 from -2 to get -4


m=-5%2F4 Reduce


So the slope of the line that goes through the points and is m=-5%2F4


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-0=%28-5%2F4%29%28x-2%29 Plug in m=-5%2F4, x%5B1%5D=2, and y%5B1%5D=0


y=%28-5%2F4%29%28x-2%29 Simplify


y=%28-5%2F4%29x%2B%28-5%2F4%29%28-2%29 Distribute


y=%28-5%2F4%29x%2B5%2F2 Multiply and reduce.


So the equation that goes through the points and is y=%28-5%2F4%29x%2B5%2F2