SOLUTION: A chemist has one solution that is 80% acid and a second solution that is 44% acid. She wants to combine the solutions to make a new solution that is 53% acid. If she needs to make

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A chemist has one solution that is 80% acid and a second solution that is 44% acid. She wants to combine the solutions to make a new solution that is 53% acid. If she needs to make      Log On


   



Question 322824: A chemist has one solution that is 80% acid and a second solution that is 44% acid. She wants to combine the solutions to make a new solution that is 53% acid. If she needs to make 320 Milliliters of this new solution, how many milliliters of the two solutions should be mixed?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 80% solution, B the amount of 44% solution.
1.A%2BB=320
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.
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80A%2B44B=53%28320%29
2.20A%2B11B=4240
From eq. 1,
A=320-B
20A=6400-20B
Substitute into eq. 2,
6400-20B%2B11B=4240
-9B=-2160
B=240
Then from eq. 1,
A%2B240=320
A=80
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.
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80 ml of 80% solution and 240 ml of 44% solution.