Question 322626: If Julia were ten more that two times her present age , she will be four times as old as she was four years ago . How old is she now .
Answer by jessica43(140)   (Show Source):
You can put this solution on YOUR website! To solve this, you need to write it as two different equations and then set them equal to each other.
First we know that at a future age (we will call this F), Julia will be 10 more than 2 times her present age (we will call this P). This can be written as:
F = (2*P) + 10
Secondly, we know at this future age she will be four times as old as she was four years ago (or present age minus 4):
F = 4* (P - 4)
Now since both equations equal F, we can set them equal to each other and solve.
(2*P)+10 = 4*(P-4) (multiply the right side out)
2P + 10 = 4P - 16 (now subtract 2P from both sides)
10 = 2P - 16 (now add 16 to both sides)
26 = 2P (divide each side by 2)
13 = P
So Julia's present age is 13 years old.
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