SOLUTION: Working together, it takes two different sized hoses 40 minutes to fill a small swimming pool. If it takes 60 minutes for the larger hose to fill the swimming pool by itself, how l

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Working together, it takes two different sized hoses 40 minutes to fill a small swimming pool. If it takes 60 minutes for the larger hose to fill the swimming pool by itself, how l      Log On


   

Question 322519: Working together, it takes two different sized hoses 40 minutes to fill a small swimming pool. If it takes 60 minutes for the larger hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on its own?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate*Time=Output
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.
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1.%28RL%2BRS%2940=Z
where Z is the volume of the pool, RL is the rate of the large hose, RS is the rate of the small hose.
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2.RL%2A60=Z
Setting equations 1 and 2 equal to each other,
%28RL%2BRS%2940=RL%2A60
40%2ARL%2B40RS=60%2ARL
40RS=20RL
RL=2%2ARS
Substituting into eq. 2,
2RS%2A60=Z
RS%2A120=Z
It would take the small hose 120 minutes to fill the pool alone.