Question 322347: in the multiplication shown, P,Q,and R are all different digits so that
P P Q
x Q
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R Q 5 Q
what is the value of P+Q+R
A 20 B 13 C 15 D 16 E 17 Answer by Jk22(389) (Show Source):
You can put this solution on YOUR website! E (17)
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Expl : Q = 5 or 6
try : Q=5 5P+2=?5 impossible
=> Q=6, 6P+3=?5 -> 6P=?2 => P=2 or 7
if P=2 : 226x6=?356, wrong, hence P=7
=> R=4 => P+Q+R=7+6+4=17 (Ans E)