SOLUTION: I am so lost on this problem. If a baseball is hit a a 36 degree angle from 3 f above the ground with a velocity of 75 mph, how long is the ball in the air and how far from home p
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Question 322061: I am so lost on this problem. If a baseball is hit a a 36 degree angle from 3 f above the ground with a velocity of 75 mph, how long is the ball in the air and how far from home plate will the ball land?
Here is what I have tried so far: v=110 ft/sec A=36 degree h=3 t = unknown
For the motion of a projectile: x = (v cos A)t and y =-16t^2+(v sin A)t+h
x = (110)(.8090)t x ~ 88.9919t
But what does that tell me? Can you please describe in detail how to solve this problem. I would appreciate the help so much.
You can put this solution on YOUR website! You have it. You just need to finish. The 88.99t tells you how far the ball travels, where t is the time in seconds.
Let's find how far it goes. Then, the time it takes to land gets entered into 88.99t to find how far it went. x is the horizontal distance and y is the vertical distance.
Set this to 0 and solve for t to find how long it takes to land.
This is a quadratic. Solving, we find t=4.087 seconds. The other solution is extraneous.
Now, to find how far it went, 88.99(4.087)=363.69 feet.
Here is a graph of the projectile motion of the baseball.
