SOLUTION: Can someone please help me to solve this one, I have tried several times, but I am doing something wrong. Please show me what to do. I tried using the quadratic formular, perhaps t

Algebra ->  Rational-functions -> SOLUTION: Can someone please help me to solve this one, I have tried several times, but I am doing something wrong. Please show me what to do. I tried using the quadratic formular, perhaps t      Log On


   

Question 321871: Can someone please help me to solve this one, I have tried several times, but I am doing something wrong. Please show me what to do. I tried using the quadratic formular, perhaps that is what I am doing incorrectly.
2sqrt(3x^(2)-2)=10
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
2sqrt%283x%5E2-2%29+=+10 Divide both sides by 2 to simplify a bit.
sqrt%283x%5E2-2%29+=+5 Square both sides.
3x%5E2-2+=+25 Add 2 to both sides.
3x%5E2+=+27 Divide both sides by 3.
x%5E2+=+9 Take the square root of both sides.
highlight%28x+=+3%29 or highlight%28x+=+-3%29
Check the solutions:
2sqrt%283x%5E2-2%29+=+10 Substitute x = 3.
2sqrt%283%283%29%5E2-2%29+=+10
2sqrt%2827-2%29+=+10
2sqrt%2825%29+=+10
2%285%29+=+10
You can try x = -3 yourself!