SOLUTION: Three cousins (Bob, Chris, Phyllis) were talking about how old they were. Bob (the oldest) noticed they were all between the ages of 11 and 30. Phyllis noticed that the sum of th

Algebra ->  Square-cubic-other-roots -> SOLUTION: Three cousins (Bob, Chris, Phyllis) were talking about how old they were. Bob (the oldest) noticed they were all between the ages of 11 and 30. Phyllis noticed that the sum of th      Log On


   

Question 32181This question is from textbook
: Three cousins (Bob, Chris, Phyllis) were talking about how old they were. Bob (the oldest) noticed they were all between the ages of 11 and 30. Phyllis noticed that the sum of their ages was 70. Chris (the youngest) pointed out that if they wrote down the square of each of their ages, all of the digits from 1 to 9 will appear exactly once in the digits of the three squares. How old were each person? This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
B+C+P=70
B~2+C~2+P~2=(1,2,3,4,5,6,7,8,9)
DON'T HAVE A FORMULA BUT SEEING AS ONLY 18~2 (324)& 19~2 (361) CONTAIN A 3 THEN
ONE OF THESE MUST BE THE AGE OF B,C OR P.
18 & 324 HAVE NO OTHER SQUARES THAT CONTAIN ALL THE MISSING NUMBERS THEREFORE 19
MUST BE ONE AGE. THE ONLY OTHER AGES AND SQUARES THAT SATISFY THE REQUIREMENTS ARE AGES OF 28 (784) AND 23 (529) OR 19+28=23=70 and 361,784,529 CONTAIN ALL THE DIGITS 1,2,3,4,5,6,7,8,9.