SOLUTION: one last question for today if anyone can please help
construct a probability distribution for the following data
number of times students were tardy to class the first quarter
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-> SOLUTION: one last question for today if anyone can please help
construct a probability distribution for the following data
number of times students were tardy to class the first quarter
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Question 321795: one last question for today if anyone can please help
construct a probability distribution for the following data
number of times students were tardy to class the first quarter
x, #of tardies 0 1 2 3 4
# of students 80 20 22 18 10
p(x)
i'm just confused on what to multiply what by to get the px..do you multiply by number of days in quarter or what....anything u can do to help is greatly appreciated! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! construct a probability distribution for the following data
number of times students were tardy to class the first quarter
x, #of tardies 0 1 2 3 4
# of students 80 20 22 18 10
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P( no tardies) = 80/150
P(one tardy) = 20/150
P(two tardies) = 22/150
P(three tardy) = 18/150
P(four tardies)= 10/150
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Cheers,
Stan H.
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