Question 321756: solve for x: log(x-2) + log(x+2) = 1
Thanks
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve for x: log(x-2) + log(x+2) = 1
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log[(x-2)(x+2)] = 1
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x^2-4 = 10^1
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x^2-14 = 0
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(x-sqrt(14)(x+sqrt(14) = 0
Possible solutions:
x = sqrt(14) or x = -sqrt(14)
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Check in the original equation:
x = sqrt(14)
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Cheers,
stan H.
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