You can put this solution on YOUR website! Well, you should know that with h(x), x is a variable. So you just substitute:
a)h(x)= 3x^2+5
h(0) means that x=0
plug in the values and use the order of operations:
h(0)=3(0)^2+5
=3(0)+5
=0+5
=5
b)h(x)= 3x^2+5
h(-1) means that x=-1
plug in the values and use the order of operations:
h(-1)=3(-1)^2+5
=3(1)+5
=3+5
=8
c)h(x)= 3x^2+5
h(4) means that x=4
plug in the values and use the order of operations:
h(4)=3(4)^2+5
=3(16)+5
=48+5
=53
d)h(x)= 3x^2+5
h(-3) means that x=-3
plug in the values and use the order of operations:
h(-3)=3(-3)^2+5
=3(9)+5
=27+5
=32
a)h(x)= 3x^2+5
h(4b) means that x=4b
just because there is a letter/variable does not mean that you change how it is done
plug in the values and use the order of operations:
h(4b)=3(4b)^2+5
=3(16b^2)+5
=(48b^2)+5
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