SOLUTION: The latent heat of fusion for ice is 79.8 cal/gram. how much ice can we melt with 1000 calories of heat? (Q=mlf)

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Question 32169This question is from textbook Strategies for problem solving
: The latent heat of fusion for ice is 79.8 cal/gram. how much ice can we melt with 1000 calories of heat? (Q=mlf) This question is from textbook Strategies for problem solving

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
THE FORMULA IS
Q=ML...WHEN CHANGE OF STATE OCCURS AT CONSTANT TEMPERATURE...AND Q=MST...WHEN CHANGE IN TEMPERATURE OCCURS WITH NO CHANGE IN STATE..SO WE USE Q=ML HERE.
1000=79.8*M
M=1000/79.8=12.5 GMS APPROXIMATELY