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Question 321380: find the intercepts of the graph of equation
y=x^2 +3x-4
rewrite the following with positive exponent
(43xy)^-8/9
please divide
(28b^3 +13b^2 + 22b + 25) / (4b+3)
multiply and simplify
81x^2/4x^2-32x+64 multiplied by 4x-16/9x
what is the value of the discriminant
20x^2-7x+13=0
thank you in advance for all your help
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the intercepts of the graph of equation
y=x^2 +3x-4
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y-intercept = ?
Let x = 0, then y = -4
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x-intercepts = ?
Let y = 0,then
x^2+3x-4 = 0
(x+4)(x-1) = 0
x = -4 or x = 1
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rewrite the following with positive exponent
(43xy)^-8/9
Note: The "negative" in the exponent tells you to invert.
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= (1/43xy)^(8/9)
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please divide
(28b^3 +13b^2 + 22b + 25) / (4b+3)
---
Using synthetic division:
-3/4)....28....13....22....25
.........28...-8.....28..|..4
Quotient: 28b^2 - 8b + 28
Remainder: 4
====================
multiply and simplify
[81x^2]/[4x^2-32x+64] * [4x-16]/9x
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Factor where you can:
[81x^2]/[4(x-4)^2] * [4(x-4)]/[9x]
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Cancel all factors that are common to a numerator and a denominator:
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= [9x]/[(x-4)] * [1]/[1]
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= 9x/(x-4)
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what is the value of the discriminant
20x^2-7x+13=0
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b^2-4ac = (-7))^2-4*20*13 = -18
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Cheers,
Stan H.
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