Question 321341: Hi, I am having a problem with two variables on a dividend when dividing polynomials. My exact problem is:
2x^3-9x^2y-12^y+17xy^2 divided by 2x-3y
I know the usual process and I have gotten to the second equation involving getting a difference of -6x^2y but now I am stuck, because when I divide -6x^2y to the first term of the divisor, I have to multiply that quotient (which is -3xy) to the brought-down -12y^3, and as far as I remember I can't multiply it because -12y^3 has no x variable. Can you please help? Thanks.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! My exact problem is:
2x^3-9x^2y-12^y+17xy^2 divided by 2x-3y
:
Rearrange the number divided, then the long division procedure will work
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(2x-3y)|2x^3 - 9x^2y + 17xy^2 - 12y^3
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I got a quotient of: x^2 - 3xy - y^2, remainder -15y^3
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