SOLUTION: If (A/30)+(B/105) = (7A+2B)/X and A, B. and X are integers greater than 1 , then what must X equal.
I have no clue where to begin...I did try multiplying x by both sides to get
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-> SOLUTION: If (A/30)+(B/105) = (7A+2B)/X and A, B. and X are integers greater than 1 , then what must X equal.
I have no clue where to begin...I did try multiplying x by both sides to get
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Question 32125: If (A/30)+(B/105) = (7A+2B)/X and A, B. and X are integers greater than 1 , then what must X equal.
I have no clue where to begin...I did try multiplying x by both sides to get rid of the x on the right side, but then from there I'm lost...
Thank You. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Multiply the 1st fraction by 7/7 to get 7A/210
Multipoy the 2nd fraction by 2/2 to get 2B/210
Add the results on the left side to get (7A+2B)/210
Compare that to the right side of the equation.
Now you can see that X=210
Cheers,
Stan H.
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