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Question 321190: i have a few questions i need help with. Your help is greatly appreciated..
express using positive exponent
b^-4
multiply
(w+d)(w^2-wd+d^2)
(-3x)^2(4x^6)^2
solve
15x^4 -31x^2 +10=0(what is the solution set)
solve what is the solution set
(x+14)(x-10)(x+1)>0
subtract the polynomial
(-4s^2 +9s+2)-(8s^2+2)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! express using positive exponent
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Comment: When there is a negative in the exponent, it
means "invert".
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b^-4 = 1/b^4
========================
multiply
(w+d)(w^2-wd+d^2)
= w(w^2-wd+d^2) + d(w^2-wd+d^2)
= w^3-w^2d+wd^2 + w^2d - wd^2 + d^3
= w^3 + d^3
------------------------------------
(-3x)^2(4x^6)^2
= (9x^2)(16x^12)
= 144x^14
===================
solve
15x^4 -31x^2 +10=0
Factor:
(3x^2-5)(5x^2-2) = 0
x = +-(5/3) or x = +-(2/5)
=====================================
(x+14)(x-10)(x+1)>0
Draw a number line and plot the boundary points
x = -14, x= -1, x = 10
Pick a check point in each of the 4 resulting intervals
to see where the solutions for the INEQUALITY lie.
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Checking x= -20 you get: -*-*- >0 false
--
Checking x = -10 you get: +*-*- >0 true
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Checking x = 5 you get: +*-*+ >0 false
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Checking x = 20 you get: +*+*+ > 0 true
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Solutions in (-inf,-14)U(-1,10)
==================================================
subtract the polynomial
(-4s^2 +9s+2)-(8s^2+2)
= -12s^2 + 9s
===================
cheers,
Stan H.
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