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Question 321101: 1. Ayie is 8 years older than Icas. The sum of their ages is 32. How old is each now?
2. A man's age is 2 years more than thrice his son's age. Find the ages of both if the sum of their ages is 46.
3. Riza's age is one year more than twice Norie's age. 8 years ago, the sum of their ages was equal to Rizza's age 10 years from now. How old are they.
(solve this in elimination method)
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! 1. Ayie is 8 years older than Icas. The sum of their ages is 32. How old is each now?
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let Icas age =x
Avie age = x+8
Their sum = 42
x+x+8=42
2x+8=42
2x=34
x=17 Icas's age
Ayie's age = x+8 = 7+8=15 years
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2. A man's age is 2 years more than thrice his son's age. Find the ages of both if the sum of their ages is 46.
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sons age =x
man's age = 3x+2
sum =46
x+3x+2=46
4x+2 = 46
4x=44
x=11, son's age
man's age = 3x+2 = 3*11 +2
=35 years
3. Riza's age is one year more than twice Norie's age. 8 years ago, the sum of their ages was equal to Rizza's age 10 years from now. How old are they.
norie's age =x
Rizza,s age =y
y=2x+1
y-2x=1.......1
8 years ago
norie's age = x-8
Rizza's age= y-8
x-8+y-8 = (y+10)
x+y-16=y+10
x=26......2
y=53
(solve this in elimination method)
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