Question 320876: Need these problem solved, I am having a hard time with my math homework and is failing. I also have 25 problem to do and is about to cry.
Just being real
Factoring completely: 18u^5 - 6u^4 - 4u^3, Factor: Y^2 = 13y + 13, Factor: 3Y^ + 2y - 21, Factoring completely: 27y^6 + 36y^5 + 12y^4, Factor the equadratic expression: Y^2 + 12y + 36, Factor: 4y^2 - z^2, Factor completely: w^4y^4 -y^4, Factoring completely: 27t^3 + 125,Factoring completely: t^2 - 2t + 1, factor: 64z^2 - 81.
Thank you
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Factoring completely:
18u^5 - 6u^4 - 4u^3,
factor out 2u^3 and you have:
2u^3(9u^2 - 3u - 2)
Factor the quadratic
2u^3(3u + 1)(3u - 2)
:
Factor: Y^2 = 13y + 13,
y^2 = 13(y + 1)
:
Factor: 3Y^2 + 2y - 21,
(3y - 7)(y + 3)
:
Factoring completely:
27y^6 + 36y^5 + 12y^4,
Factor our 3y^4
3y^4(9y^2 + 12y + 4)
Quadratic is a perfect square
3y^4(3y + 2)(3y + 2)
:
Factor the quadratic expression:
Y^2 + 12y + 36,
Also a perfect square
(y + 6)(y + 6)
:
Factor: 4y^2 - z^2,
The difference of squares
(2y + z)(2y - z); check this by FOILing
:
Factor completely:
w^4y^4 -y^4,
Factor out y^4
y^4(w^4 - 1)
factor the difference of square
y^4(w^2 - 1)(w^2 + 1)
Another dif of squares, so you have:
y^4(w-1)(x+1)(w^2+1)
:
Factoring completely: 27t^3 + 125,
This is the sum of cubes, requires special factoring, look up "sum of cubes"
(3t + 5)(9t^2 - 5t + 25)
:
Factoring completely:
t^2 - 2t + 1,
perfect square
(t - 1)(t - 1)
:
factor: 64z^2 - 81.
Difference of squares
(8z - 9)(8z + 9)
:
:
Please don't cry now!
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! Factoring completely: 18u^5 - 6u^4 - 4u^3,
Common Factor: 2u^3(6u^2 - 3u - 2)
--------------------------------------------
Factor: Y^2 = 13y + 13
Y^2-13Y-13
Can only be factored using the quadratic formula
--------------------------------------------
Factor: 3Y^ + 2y - 21
Can only be factored using the quadratic formula.
--------------------------------------------
Factoring completely: 27y^6 + 36y^5 + 12y^4
Common Factor: 3y^4
Factors: 3y^4(9y^2 + 12y + 4)
Can be further factored using the quadratic formula.
---------------------------------------------
Factor the equadratic expression: Y^2 + 12y + 36
Factor form: (y+6)^2
---------------------------------------------
Factor: 4y^2 - z^2
Factor Form: (2y-z)(2y+z)
---------------------------------------------
Factor completely: w^4y^4 -y^4
Factor Form: y^4(w^4-1)
= y^4(w^2+1)(w+1)(w-1)
---------------------------------------------
Factoring completely: 27t^3 + 125
= (3t)^3 + 5^3
---
= (3t+5)((3t)^2 - (3t)(5) + 5^2)
---
= (35+5)(9t^2 - 15t + 25)
----------------------------------------------
Factoring completely: t^2 - 2t + 1
Factor Form: (t-1)^2
----------------------------------------------
factor: 64z^2 - 81
(8z)^2 - 9^2
---
= (8z+9)(8z-9)
==================
Cheers,
Stan H.
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