Question 32085This question is from textbook 9781592009428
: Goodevening.I would like to beg you, please help me in this problems
1)The total interest earned on a sum of money invested for one year was $183. If the $500 more was invested at 1o% simple interest than was invested at 9% simple interest, how much was invested at each rate?
2) geometry problem
In a 30,60 right triangle, if the opposite side of right angle is 6 units, find the area of triangle.
your poor studnent Emmamodi
This question is from textbook 9781592009428
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Let amount invested at 9% be "x"
Then amount invested at 10% must be "x+500"
Interest on the 9% investment is 0.09x
Interest on the 10% investment is .10(x+500)=0.10x+50
EQUTION:
Interest + Interest = $183
0.09x + 0.10x+50 = 183
9x + 10x + 5000 = 18300
19x= 13300
x=$700 (amount invested at 9%)
x+500= $1200 (amount invested at 10%)
Cheers,
Stan H.
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