Question 320768: Write an equation of the line containing the given point and parallel to the given line. Express in the form of y=mx+b,
1. (4,7); x+6y=7
2. (-4,7); 8x=5y+3
3. (6,8); 3x+y=8
4. (4,-9); 9x+7y=8
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! 1. (4,7); x+6y=7
6Y=-X+7
Y=-X/6+7/6
Y=mX+b
THIS LINE HAS A SLOPE(m)=-1/6
ANY PARALLEL LINE WILL ALSO HAVE A SLOPE=-1/6
NOW REPLACE X & Y, IN THE LINE EQUATION, WITH (4,7) & SOLVE FOR b (THE Y INTERCEPT).
7=-1/6*4+b
7=-4/6+b
7+2/3+b
b=21/3+2/3
b=23/3 ans for the Y intercept.
Y=-X/6+23/3
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -x/6 +23/3).
I'VE SOLVED THE FIRST PROBLEM.
I'LL LEAVE THE REST FOR YOU TO PRACTICE ON.
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2. (-4,7); 8x=5y+3
3. (6,8); 3x+y=8
4. (4,-9); 9x+7y=8
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