SOLUTION: Simplify. Assume that no denominator is 0 and that 00is not considered. (a^3 b)(ab)^4 can some one show me how to work this problem out what do i plug in for a a b

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Simplify. Assume that no denominator is 0 and that 00is not considered. (a^3 b)(ab)^4 can some one show me how to work this problem out what do i plug in for a a b      Log On


   



Question 320716: Simplify. Assume that no denominator is 0 and that 00is not considered.
(a^3 b)(ab)^4
can some one show me how to work this problem out what do i plug in for a a b

Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
All you can do for this expression is simplify using the laws of exponents.
%28a%5E3+b%29%28ab%29%5E4+=a%5E%283%2B4%29b%5E%281%2B4%29
%28a%5E3+b%29%28ab%29%5E4+=a%5E%287%29b%5E%285%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify. Assume that no denominator is 0 and that 00is not considered.
(a^3 b)(ab)^4
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= (a^3 b)(a^4 b^4)
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= (a^3*a^4)(b*b^4)
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= a^7*b^5
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Cheers,
Stan H.
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