Question 320494: I was wondering if I can get help answering this problem. I chose #1
Sex X Mean St Dev SE Mean
F 116 1.95 1.51 0.14
M 59 2.37 1.87 0.24
(95% CI for mu(f) - mu(m):(-0.97,0.14)
T-Test mu(f)=mu(m) (vs not =): T= -1.49 P=0.14 DF=97
For the variable "Time spent watching TV in Typical Day," the results of a two-sample t-procedure that compares a random sample of men and women at a college are shown above. What is the alternative hypothesis of the t-test?
1. μ1 − μ2 < 0
2. μ1 − μ2 = 0
3. μ1 − μ2 ≠ 0
4. μ1 − μ2 >
Thanks,
Kim
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I was wondering if I can get help answering this problem. I chose #1
Sex X Mean St Dev SE Mean
F 116 1.95 1.51 0.14
M 59 2.37 1.87 0.24
(95% CI for mu(f) - mu(m):(-0.97,0.14)
T-Test mu(f)=mu(m) (vs not =): T= -1.49 P=0.14 DF=97
For the variable "Time spent watching TV in Typical Day," the results of a two-sample t-procedure that compares a random sample of men and women at a college are shown above. What is the alternative hypothesis of the t-test?
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Your problem statement says you are testing mu(f) = mu(m) (vs not =)
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Since Ho must ALWAYS include equality, the
alternate hypotheses is mu(f)-mu(m) is not equal to 0
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Cheers,
Stan H.
1. μ1 − μ2 < 0
2. μ1 − μ2 = 0
3. μ1 − μ2 ≠ 0
4. μ1 − μ2 >
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