SOLUTION: if sally can paint a house in 4hrs and john can paint the same house in 6hrs, how long will it take for both of them to paint the house together
Question 320236: if sally can paint a house in 4hrs and john can paint the same house in 6hrs, how long will it take for both of them to paint the house together Found 2 solutions by Edwin McCravy, Alan3354:Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! if sally can paint a house in 4hrs and john can paint the same house in 6hrs, how long will it take for both of them to paint the house together
The easy way to do it is this way, which you can do in your head:
4 and 6 both go into 12. In 12 hours Sally can paint 3 houses and
John can paint 2 houses. So that's 5 houses in 12 hours, or 1 house
in hours or hours, or 2 hours 24 minutes.
But your teacher doesn't want you to do it that easy way.
Your teacher wants you to make this chart, get an equation
and solve it:
number time rate in
of required houses
houses in per
painted hours hour
--------|-----------|-----------|----------
Sally | | |
--------|-----------|-----------|----------
John | | |
--------|-----------|-----------|----------
Both | | |
--------|-----------|-----------|----------
Let x be the number of hours required for both.
So fill in x in the middle on the bottom row,
for the time for both to paint one house working
together.
number time rate in
of required houses
houses in per
painted hours hour
--------|-----------|-----------|----------
Sally | | |
--------|-----------|-----------|----------
John | | |
--------|-----------|-----------|----------
Both | | x |
--------|-----------|-----------|----------
Next fill in the times, 4 for Sally and 6 for John
number time rate in
of required houses
houses in per
painted hours hour
--------|-----------|-----------|----------
Sally | | 4 |
--------|-----------|-----------|----------
John | | 6 |
--------|-----------|-----------|----------
Both | | x |
--------|-----------|-----------|----------
We are only talking about them painting 1 house so we
fill in 1 for the number of houses painted in all three
cases:
number time rate in
of required houses
houses in per
painted hours hour
--------|-----------|-----------|----------
Sally | 1 | 4 |
--------|-----------|-----------|----------
John | 1 | 6 |
--------|-----------|-----------|----------
Both | 1 | x |
--------|-----------|-----------|----------
Next we fill in the rates in houses/hour by
dividing the number of houses by the number
of hours
number time rate in
of required houses
houses in per
painted hours hour
--------|-----------|-----------|----------
Sally | 1 | 4 |
--------|-----------|-----------|----------
John | 1 | 6 |
--------|-----------|-----------|----------
Both | 1 | x |
--------|-----------|-----------|----------
Then we form the equation from:
(Sally's rate) + (John's rate) = (rate for both together)
Multiply through by LCD = 12x
or hours, or 2 hours 24 minutes
Edwin
You can put this solution on YOUR website! Sally does 1/4 house per hour.
John paints 1/6 house per hour.
Together, they do 1/4 + 1/6 per hour = 10/24 houses per hour.
Hours per house = 24/10 = 2.4 hours
-------------------
If you're pressed for time, as on a test, use the shortcut, product/sum
4*6/(4+6) = 24/10
= 2.4 hours