SOLUTION: soybean meal is 14% protein;cornmeal is 7% protein, how many pounds of each should be mixed together in order to get 280-lb mixture that is 11% protein?

Algebra ->  Linear-equations -> SOLUTION: soybean meal is 14% protein;cornmeal is 7% protein, how many pounds of each should be mixed together in order to get 280-lb mixture that is 11% protein?      Log On


   

Question 320206: soybean meal is 14% protein;cornmeal is 7% protein, how many pounds of each should be mixed together in order to get 280-lb mixture that is 11% protein?
Found 2 solutions by checkley77, nyc_function:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.14x+.07(280-x)=.11*280
.14x+19.6-.07x=30.8
.07x=30.8-19.6
.07x11.2
x=11.2/.07
x=160 lbs. of soybeans are used.
280-160=120 lbs. of cornmeal is used.
Proof:
.14*160+.07*120=.11*280
22.4+8.4=30.8
30.8=30.8

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
first mixture + second mixture = total mixture
Let p = how many pounds
I believe the equation you need is:
p(0.14) + p(0.07) = 0.11(2p + 280)
Can you finish?