Question 320177: •A car and a bus set out at 2 p.m. from the same point, headed in the same direction. The average speed of the car is 30 mph slower than twice the speed of the bus. In two hours, the car is 20 miles ahead of the bus. Find the rate of the car.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A car and a bus set out at 2 p.m. from the same point, headed in the same direction. The average speed of the car is 30 mph slower than twice the speed of the bus. In two hours, the car is 20 miles ahead of the bus. Find the rate of the car.
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Bus DATA:
rate = x mph ; time = 2 hrs ; distance = 2x miles
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Car DATA:
rate = 2x-30 ; time = 2 hrs ; distance = 2(2x-30) = 4x-60 miles
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Equation:
car distance - bus distance = 20 miles
4x-60-2x = 20
2x = 80
x = 40 mph (bus speed)
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Car rate = 2x-30 = 2*40-30 = 50 mph
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Cheers,
Stan H.
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