SOLUTION: How do you convert an equation from slope-intercept form into standard form (Ax + By = C) I have two; y= -3/4x - 3/2 y= 3/5x + 3 I've worked through the firs

Algebra ->  Linear-equations -> SOLUTION: How do you convert an equation from slope-intercept form into standard form (Ax + By = C) I have two; y= -3/4x - 3/2 y= 3/5x + 3 I've worked through the firs      Log On


   



Question 320011: How do you convert an equation from slope-intercept form into standard form (Ax + By = C)
I have two; y= -3/4x - 3/2
y= 3/5x + 3
I've worked through the first from some online instructions, and get 4y= -3x -12
but have no idea what I am doing... Help?!?!?! I will be eternally grateful for your assistance!! --Sandy

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the capital letters indicate integer coefficients (no fractions)
___ by convention , the x coefficient is positive
___ this means you have to get the x's and y's on one side and the constant on the other
___ multiply by the appropriate "fudge" factors so everything fits the format

y= -3/4x - 3/2 ___ multiply by 4 to clear fractions ___ 4y = -3x - 6
___ add 3x ___ 3x + 4y = -6

y= 3/5x + 3 ___ multiply by 5 to clear fractions ___ 5y = 3x + 15
___ subtract 3x ___ -3x + 5y = 15
___ multiply by -1 ___ 3x - 5y = -15