You can put this solution on YOUR website! use elimination method
3r - 5s = -7
5r + 3s = 45
:
We are going to multiply each equation by a value that will make the coefficient
of s in each equation to be equal
:
Multiply the 1st equation by 3, multiply the 2nd equation by 5, results
9r - 15s = -21
25r+ 15s = 225
------------------adding eliminates s, find r
34r + 0s = 204
r =
r = 6
:
Use the 2nd original equation to find s, substitute 6 for r
5(6) + 3s = 45
30 + 3s = 45
3s = 45 - 30
3s = 15
s =
s = 5
;
:
Check solutions in the original 1st equation
9r - 15s = -21
9(6) - 15(5) =
54 - 75 = -21; confirms our solutions, Make sense to you now?
