SOLUTION: Solve for x x^3 + 3x^2 - 4x - 12 = 0
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Question 31967
This question is from textbook
Intermedate Algebra
:
Solve for x
x^3 + 3x^2 - 4x - 12 = 0
This question is from textbook
Intermedate Algebra
Answer by
stanbon(75887)
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x^2(x+3)-4(x+3)=0
(x+3)(x^2-4)=0
(x+3)(x-2)(x+2)=0
x=-3 or x=2 or x=-2
Cheers,
Stan H.