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Question 319570: solve each system of equations algebraically
1/x + 3/y = 6
2/x -1/y = 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve each system of equations algebraically
1/x + 3/y = 6
2/x -1/y = 1
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Let 1/x = a
Let 1/y = b
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Rewrite the equations:
a + 3b = 6
2a - b = 1
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Multiply thru 1st equation by 2 to get:
2a + 6b = 12
2a - b = 1
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Subtract 2nd from 1st and solve for "b:
7b = 11
b = 11/7
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Since a = 6-3b, a = 6-33/7 = 9/7
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Since a = 1/x, x = 7/9
Since b = 1/y, y = 7/11
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Cheers,
Stan H.
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