SOLUTION: find a number that is twice its square root,increased by 7 is 9

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Question 319415: find a number that is twice its square root,increased by 7 is 9
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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find a number that is twice its square root,increased by 7 is 9
:
2sqrt%28x%29 + 7 = 9
:
2sqrt%28x%29 = 9 - 7
2sqrt%28x%29 = 2
square both sides
4x = 4
x = 1
:
Check solution in original equation
2sqrt%281%29 + 7 = 9
2(1) + 7 = 9