Question 319293: 1. Find an equation of the line satisfying the conditions given. Express your answers in standard form. Please explain.
Parallel to 3x - y = -5 and pasing through (-1, 0)
2. Without graphing determine whether the following pairs of lines are (a paralell), (b) perpindicular, or (c) neither.
5x - 6y = 19
6x + 5y = -30
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1. Find an equation of the line satisfying the conditions given. Express your answers in standard form. Please explain.
Parallel to 3x - y = -5 and pasing through (-1,0)
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A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
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The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
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Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
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For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
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2. Without graphing determine whether the following pairs of lines are (a paralell), (b) perpindicular, or (c) neither.
5x - 6y = 19
6x + 5y = -30
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Find the slope of each line. To do that, put the equations in slope-intercept form (that means solve for y).
If the slopes are the same, they're parallel.
If the product of the slopes = -1, they're perpendicular.
If neither, then (c) neither.
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