SOLUTION: Samia walks for a time at 4mph, then slows down and walks at 3.2mph. The total distance she walked was 6 miles. If she walked for 0.5 hour more at 3.2 mph than she did at 4mph, det
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Question 319190: Samia walks for a time at 4mph, then slows down and walks at 3.2mph. The total distance she walked was 6 miles. If she walked for 0.5 hour more at 3.2 mph than she did at 4mph, determine the time Samia walked at 4mph. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Samia walks for a time at 4mph, then slows down and walks at 3.2mph.
The total distance she walked was 6 miles.
If she walked for 0.5 hour more at 3.2 mph than she did at 4mph,
determine the time Samia walked at 4mph.
:
Let t = time walked at 4 mph
then
(t+.5) = time walked at 3.2 mph
:
Write a distance equation: dist = speed * time
:
dist at 4 + dist at 3.2 = 6 miles
4t + 3.2(t+.5) = 6
:
4t + 3.2t + 1.6 = 6
:
7.2t = 6 - 1.6
;
7.2t = 4.4
t =
t = .611 hrs at 4 mph
and
.611 + .5 = 1.111 hrs at 3.2 mph
:
:
Check solution by finding the distances
.611 * 4 = 2.44 mi
1.11 * 3.2 = 3.55 mi
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total dist: 5.99 ~ 6 mi
