SOLUTION: What is the range of g if {{{"g(x)"=sqrt(x-3)+2}}}?

Algebra ->  Square-cubic-other-roots -> SOLUTION: What is the range of g if {{{"g(x)"=sqrt(x-3)+2}}}?      Log On


   



Question 319099: What is the range of g if %22g%28x%29%22=sqrt%28x-3%29%2B2?
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!

%22g%28x%29%22=sqrt%28x-3%29%2B2

What's under a square root radical must be %22%22%3E=0, so

x-3%3E=0

So the domain of g is x%3E=3 or [3,infinity)

Now we built 

x-3%3E=0

up to the right side of g(x)

Take positive square roots of both sides:

sqrt%28x-3%29%3E=sqrt%280%29

sqrt%28x-3%29%3E=0

Add 2 to both sides:

sqrt%28x-3%29%2B2%3E=2

So the left side now equals g(x), so

g%28x%29%3E=2

So the range of g is [2,infinity).

graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Csqrt+%28+x+-+3+%29+%2B+2%29.

Edwin