SOLUTION: A telephone company offers two long-distance plans. Plan A: $25 per month and .05 per minute Plan B: $5 per month and .12 per minute For how many minutes of long-distance calls

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Question 31906This question is from textbook College Algebra
: A telephone company offers two long-distance plans.
Plan A: $25 per month and .05 per minute
Plan B: $5 per month and .12 per minute
For how many minutes of long-distance calls would plan B be finanically advantageous?
Thank you very much!
This question is from textbook College Algebra

Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
Let's call X to the number of minutes of long-distance calls you plan to make.
The cost of plan A is given by 25%2B0.05X
The cost of plan B is given by 5%2B0.12X
Plan B is advantageous when its cost is lower than plan A's. Therefore, we set the inequality
5%2B0.12X+%3C+25%2B0.05X
And then solve for X. This will give us the range of minutes for which B is more convenient.
Subtract 5 from both sides of the inequality to get:
0.12X+%3C+20%2B0.05X
Now subtract 0.05X:
0.12X+-+0.05X+%3C+20
0.07X%3C20
Finally, divide by 0.07 to get:
X+%3C+20%2F0.07
X++%3C+285.71
So plan B is advantageous if you plan to use less than 286 minutes of long distance calls.

I hope this helps!
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