SOLUTION: What three consecutive odd numbers have a product of 12075?

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Question 319011: What three consecutive odd numbers have a product of 12075?
Answer by CharlesG2(834) About Me  (Show Source):
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What three consecutive odd numbers have a product of 12075?
factoring 12075
12075 = 25 * 483
(483 must be divisable by 3
because 4 + 8 + 3 = 15 and that is divisable by 3)
12075 = 25 * 3 * 161
(161 must be divisable by 7
because 7 * 10 = 70, 70 * 2 = 140, 3 * 7 = 21, and 140 + 21 = 161)
12075 = 25 * 3 * 7 * 23
(23 is a prime number, so it can not be factored)
12075 = 21 * 23 * 25 (these are your consecutive odd numbers)