SOLUTION: How many solutions are there to the equality | x - |2x + 1| | = 3?
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Question 319009
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How many solutions are there to the equality | x - |2x + 1| | = 3?
Answer by
CharlesG2(834)
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How many solutions are there to the equality | x - |2x + 1| | = 3?
| x - |2x + 1| | = 3
this is equivalent to
x - |2x + 1| = -3 OR x - |2x + 1| = 3
-|2x + 1| = -3 - x -|2x + 1| = 3 - x
|2x + 1| = x + 3 |2x + 1| = x - 3
|2x + 1| = x + 3
this is equivalent to
2x + 1 = -(x + 3) OR 2x + 1 = x + 3
2x + 1 = -x - 3 x = 2
3x = -4
x = -4/3
2 Solutions
check:
| x - |2x + 1| | = 3 plug in -4/3
| (-4/3) - |2(-4/3) + 1| | = 3
| -4/3 - |-8/3 + 1| | = 3
| -4/3 - |-5/3| | = 3
| -4/3 - 5/3 | = 3
| -9/3 | = 3
9/3 = 3
| x - |2x + 1| | = 3 plug in 2
| (2) - |2(2) + 1| | = 3
| 2 - |4 + 1| | = 3
| 2 - 5 | = 3
| -3 | = 3
3 = 3
2 Solutions