SOLUTION: Explain whether the equation 3(x – 1) + 5 = 15x + 7 – 4 – 4(3x +1) + 3 has infinitely many solutions, one solution, or no solutions?

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Question 318969: Explain whether the equation 3(x – 1) + 5 = 15x + 7 – 4 – 4(3x +1) + 3 has infinitely many
solutions, one solution, or no solutions?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3%28x-1%29+%2B+5+=+15x+%2B+7-+4-4%283x%2B1%29+%2B+3
3x-3%2B5=15x%2B6-12x-4
3x%2B2=3x%2B2
0=0
True for all x.
Infinitely many solutions.