Question 318798: Divide: (20b^3+7b^2+22b+23) divided by (4b+3)
Answer by CharlesG2(834)   (Show Source):
You can put this solution on YOUR website! Divide: (20b^3+7b^2+22b+23) divided by (4b+3)
okay this is just like a regular long division problem, except you got the variable b thrown in there
5b^2 - 2b + 7
4b + 3 --> 20b^3 + 7b^2 + 22b + 23
20b^3 + 15b^2
- 8b^2 + 22b
- 8b^2 - 6b
28b + 23
28b + 21
2 (there is a remainder)
5b^2 - 2b + 7 + 2/(4b + 3)
check (4b + 3)(5b^2 - 2b + 7):
20b^3 - 8b^2 + 28b
+ 15b^2 - 6b + 21 =
20b^3 + 7b^2 + 22b + 21
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